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3m^2-17m+5=0
a = 3; b = -17; c = +5;
Δ = b2-4ac
Δ = -172-4·3·5
Δ = 229
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{229}}{2*3}=\frac{17-\sqrt{229}}{6} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{229}}{2*3}=\frac{17+\sqrt{229}}{6} $
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